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Mathematics 21 Online
OpenStudy (anonymous):

if cot of theta = -9/2 with theta in Quadrant 2, find the sin of theta

OpenStudy (campbell_st):

well using the information then tan = -2/9 so draw a diagram |dw:1403640424456:dw|

OpenStudy (anonymous):

4+81=h^2 h=9.2 or h=sqrt85

OpenStudy (campbell_st):

I'd use sqrt85 that way you have an exact value.... now you can get the sin of theta... opp/hyp

OpenStudy (anonymous):

sin of theta = 2/9.2

OpenStudy (anonymous):

2/ sqrt85

OpenStudy (campbell_st):

yes... I'd use the 2nd answer.... rather than the decimal

OpenStudy (anonymous):

ok thank you i was just wondering though how did you know witch way to face your triangle when you put in the quadrant

OpenStudy (anonymous):

|dw:1403641221648:dw| how do you know to put it that way instead of this way

OpenStudy (campbell_st):

ok.... well there is a standard from.... 2nd quadrant is always 180 - theta they look like |dw:1403641021294:dw|

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