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if cot of theta = -9/2 with theta in Quadrant 2, find the sin of theta
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well using the information then tan = -2/9 so draw a diagram |dw:1403640424456:dw|
4+81=h^2 h=9.2 or h=sqrt85
I'd use sqrt85 that way you have an exact value.... now you can get the sin of theta... opp/hyp
sin of theta = 2/9.2
2/ sqrt85
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yes... I'd use the 2nd answer.... rather than the decimal
ok thank you i was just wondering though how did you know witch way to face your triangle when you put in the quadrant
|dw:1403641221648:dw| how do you know to put it that way instead of this way
ok.... well there is a standard from.... 2nd quadrant is always 180 - theta they look like |dw:1403641021294:dw|
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