Question

An object is acted on by the force shown in the figure I'll provide. Thanks in advanced

What is the final position of the object if its initial position is x = 0.40 m and the work done on it is equal to -0.19 J?

Answer 1

First, remember this equation:

\[W=F \Delta d\]
W is work
F is applied force
Δd is the change in displacement (final - initial)

We have work and initial displacement already. Looking at the graph, we also have force - when x=0.40 m, F=0.8 N. We can plug these values into the equation to solve for the final displacement (d):

-0.19 = 0.8 x (d - 0.4)
d = 0.1625 m