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What is the mass percent of solute in a solution formed by dissolving 0.365 mol NaI in 275 mL of water? Assume a water density of 1.0 g/mL.
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Calculate Molar Mass of Sodium Iodide:149( g/mol) 1 Mole of NaI--->149grams 0.365 Mole Of NaI---> x grams x=0.365*149/1 x=54.385 grams Mass of Solution=Mass Of Water+Mass Of Sodium Iodie 1 Gram Represent 1 cm^3 Mass of Solution=275+54.385 =329.385 grams The Solute Here is the sodium iodide and the solvent is Water mass percent of solute in the solution would be calculated Total Mass of Solute/Total Mass of Solution
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