Barbie is analyzing a circle, y2 + x2 = 16, and a linear function g(x). Will they intersect? x g(x) 0 6 1 3 2 0
@mathmate
Yes, at positive x-coordinates or zero Yes, at negative x-coordinates or zero Yes, at negative and positive x-coordinates or zero No, they will not intersect
@mathmate
@mathmale
The circle is centred at the origin, with a radius of 4. One of the points of the line (2,0) is inside the circle. So the line must intersect the circle.
at first you have to decide if they intersect or not. trick is to decide the distance of the points (x,g(x)) from the origin. so you know (0,6) is out of the circle but (1,3) is inside the circle. That is enough to decide that those two intersect
ok
Also, the point (0,6) is outside the circle, and (2,0) is inside, so there cannot be any intersection when x<0.
ok
but there is (1,3)
(1,3) has x>0, so that's not a problem. All you need to know is if there is any intersection for x<0.
ok so there is an intersection at th postive x intercept
There are two intersections, both with positive x-coordinates.
so then it will be A again
@mathmate
yes.
Is it A again
It took me a while to understand the statement, actually it was trying to say \[x\ge0\]
so is It A again
@mathmate its A again right?
Yes it is A again.
thanks
can you help me with one more
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