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OpenStudy (anonymous):
Triangle ABC is congruent to triangle DEF. In triangle ABC, side AB measures 13, side BC measures x+13, and side CA measures 16. In triangle DEF, side DE measures 13, side EF measures 3x−20, and side FD measures 16. What equation would help you to solve for the side length of BC and EF?
OpenStudy (anonymous):
can someone show me how to solve this problem ? i dont wanna just know the answer
OpenStudy (anonymous):
@mathmale
OpenStudy (anonymous):
@ganeshie
OpenStudy (anonymous):
@ganeshie8
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OpenStudy (anonymous):
ABC and DEF are congruent. So
AB = DE = 13
CA = FD = 16 and
BC = EF
i.e x+13 = 3x−20
Solve this eqn for x and then calculate BC and EF.
Does this help ?
OpenStudy (anonymous):
yes hold on
OpenStudy (anonymous):
i cant even solve the equation
OpenStudy (anonymous):
i get -7=2x
OpenStudy (anonymous):
or -2x=-23
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OpenStudy (anonymous):
am i suppose to solve for x right ? @ShailKumar
OpenStudy (anonymous):
Yes. solve for x.
OpenStudy (anonymous):
-2x=-33
OpenStudy (anonymous):
x+13=3x-20
+20 +20
x+33=3x
-x -x
33=2x
OpenStudy (anonymous):
so like x is like 16.5
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OpenStudy (anonymous):
Right! Now calculate BC and EF
OpenStudy (anonymous):
they both equal 29.5
OpenStudy (anonymous):
That's right! They should be for they are congruent triangles.
OpenStudy (anonymous):
my gosh thanks
man
OpenStudy (anonymous):
Welcome :)
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