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Integrate (x^2).(e^-x) with respect to x.
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have you tried by parts?
\[u=x^2,dv=e^{-x}\]
I tried that and I got to -x^2.e^-x+∫e^-x 2xdx I don't know what to do with that 2xdx when integrating.
repeat the process that happens a lot in integration by parts
\[u=2x\\dv=e^{-x}\]
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indeed, integration by parts applied 2 times :)
Oh right! I got the answer to be -e^-x . (x^2+2x+2) thanks for the help guys
:)
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