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Mathematics 13 Online
OpenStudy (anonymous):

@phi I have a few more just as confusing as the previous one. @Johnbc

OpenStudy (anonymous):

OpenStudy (turingtest):

do you know what that circle notation means?

OpenStudy (anonymous):

no, I know it's not multiplication; that's why I'm confused.

OpenStudy (turingtest):

\[(f\circ g)(x)=f[g(x)]\]in other notation

OpenStudy (anonymous):

It means, a function composed of another function.

OpenStudy (turingtest):

in other words, you put the second function inside the first

OpenStudy (anonymous):

In this specific case.

OpenStudy (turingtest):

for example, if\[f(x)=x^2\]and\[g(x)=x+1\]then\[(f\circ g)(x)=f[g(x)]=f(x+1)=(x+1)^2\]

OpenStudy (turingtest):

notice how the whole expression for g(x) went where the 'x' goes in f(x)

OpenStudy (anonymous):

yes.

OpenStudy (anonymous):

but I keep getting -2x^2-3

OpenStudy (turingtest):

could you show your work, please?

OpenStudy (anonymous):

-may you work this out with me? I multiplied 2x^2-4x times x-3

OpenStudy (turingtest):

well, as per my explanation above, the circle does *not* mean multiply, but to put one function inside the other so you want to put the expression for g(x) where the x is in the expression for f(x) 2[g(x)]^2-4[g(x)] now write out the expression for g(x) and simplify

OpenStudy (anonymous):

I got c for the answer, correct?

OpenStudy (turingtest):

yes :)

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