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Mathematics 23 Online
OpenStudy (hanner_b_nanner):

I need help pleeaasseee!! :D Fan&&Medal Matt is constructing two similar triangles for an art project. The drawing below shows Matt's plans, but there is an error in his drawing. What changes would he make to the dimensions to change the error? Explain your reasoning using complete sentences.

OpenStudy (hanner_b_nanner):

OpenStudy (mathstudent55):

The ratios of the lengths of any two corresponding sides of similar triangles is the same. Can you name the three pairs of corresponding sides?

OpenStudy (hanner_b_nanner):

Okay, A=D, B=E, and C=F.

OpenStudy (hanner_b_nanner):

@Squirrels

OpenStudy (mathstudent55):

Sorry, I lost connection for a while. I'm back now.

OpenStudy (mathstudent55):

Correct. Those are the corresponding vertices.

OpenStudy (hanner_b_nanner):

Oh, ok... lol :D

OpenStudy (mathstudent55):

Since the triangles are similar, when you divide the length of a side of one triangle by the length of the corresponding side of the other triangle, you get a number. This number must be the same for all pairs of corresponding sides.

OpenStudy (mathstudent55):

Here are the corresponding sides and their lengths: DE and AB; 12.5 and 10 DF and AC; 10.5 and 8 EF and BC; 18.75 and 15 Ok so far?

OpenStudy (hanner_b_nanner):

Ok, got that...

OpenStudy (mathstudent55):

Each of these pairs can be written as a ratio of lengths. \(\dfrac{DE}{AB} = \dfrac{12.5}{10}\) \(\dfrac{DF}{AC} = \dfrac{10.5}{8}\) \(\dfrac{EF}{BC} = \dfrac{18.75}{15}\)

OpenStudy (mathstudent55):

Notice the left fractions. They are ratios of lengths of corresponding sides.

OpenStudy (hanner_b_nanner):

Right

OpenStudy (mathstudent55):

For two triangles to be similar, all ratios must be equal. Are they? Divide the fractions out and see what each fraction is equal to as a decimal. Are all fractions equal in value?

OpenStudy (hanner_b_nanner):

DE/AB=12.5/10 -1.25 DF/AC=10.5/8 -1.3125 EF/BC=18.75/15 -1.25 No, the length needs to be changed on the side DF/AC.

OpenStudy (hanner_b_nanner):

t needs to be 10/8, right?

OpenStudy (hanner_b_nanner):

It*

OpenStudy (mathstudent55):

Correct.

OpenStudy (hanner_b_nanner):

Ok, thank you!!!!! I kept looking at it knowing that it was a ratio, but my mind like went blank lol :))

OpenStudy (mathstudent55):

You figured it out in the end. Good job! You're welcome.

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