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Mathematics 9 Online
OpenStudy (anonymous):

What is the line of symmetry? https://media.glynlyon.com/g_alg02_ccss_2013/8/equation_parabola.gif x-axis y-axis x = p x = -p

OpenStudy (jdoe0001):

\(\bf y=\cfrac{1}{4p}x^2\implies 4py=x^2\implies 4p(y-{\color{blue}{ 0}})=(x-{\color{blue}{ 0}})^2\) what do you think it's?

OpenStudy (anonymous):

I think it's x=p

OpenStudy (jdoe0001):

do you know where the vertex is at?

OpenStudy (anonymous):

no, but I know it's not y-axis

OpenStudy (jdoe0001):

hehe

OpenStudy (jdoe0001):

\(\bf y=\cfrac{1}{4p}x^2\implies 4py=x^2\implies 4p(y-{\color{blue}{ 0}})=(x-{\color{blue}{ 0}})^2\qquad {\color{blue}{ vertex}}\) so... what do you think is the axis of symmetry?

OpenStudy (anonymous):

x=-p

OpenStudy (anonymous):

Y-axis was my 1st answer but it was incorrect

OpenStudy (jdoe0001):

notice, the "x" is the squared term meaning, the parabola is going upwards or downwards and the coefficient of the leading term is positive

OpenStudy (jdoe0001):

hmm

OpenStudy (jdoe0001):

the 4p is simply going to make WIDER but the vertex would still be the origin and the leading term coefficient is positive, so is going upwards |dw:1403740151712:dw|

OpenStudy (anonymous):

so it would be x-axis??

OpenStudy (anonymous):

so it would be on the x axis but the line of symmetry would be x=p

OpenStudy (anonymous):

@jdoe0001

OpenStudy (jdoe0001):

hmmm on the x-axis? it'd be the y-axis |dw:1403740898842:dw|

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