What is the line of symmetry? https://media.glynlyon.com/g_alg02_ccss_2013/8/equation_parabola.gif x-axis y-axis x = p x = -p
\(\bf y=\cfrac{1}{4p}x^2\implies 4py=x^2\implies 4p(y-{\color{blue}{ 0}})=(x-{\color{blue}{ 0}})^2\) what do you think it's?
I think it's x=p
do you know where the vertex is at?
no, but I know it's not y-axis
hehe
\(\bf y=\cfrac{1}{4p}x^2\implies 4py=x^2\implies 4p(y-{\color{blue}{ 0}})=(x-{\color{blue}{ 0}})^2\qquad {\color{blue}{ vertex}}\) so... what do you think is the axis of symmetry?
x=-p
Y-axis was my 1st answer but it was incorrect
notice, the "x" is the squared term meaning, the parabola is going upwards or downwards and the coefficient of the leading term is positive
hmm
the 4p is simply going to make WIDER but the vertex would still be the origin and the leading term coefficient is positive, so is going upwards |dw:1403740151712:dw|
so it would be x-axis??
so it would be on the x axis but the line of symmetry would be x=p
@jdoe0001
hmmm on the x-axis? it'd be the y-axis |dw:1403740898842:dw|
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