Question

. For the quantum number the = 2, how many possible values are there for the quantum number m subscrip l?

2
3
5
6

Answer 1

@Abmon98 can u help?

Answer 2

@abb0t

Answer 3

I'll give u an example !
Let us calculate everything for Principal Quantum number P

Answer 4

Azimuthal Quantum number (l) = Principal Quantum number (n) - 1,
So here value for l = 1-1=0

Answer 5

Magnetic quantum number (m) = -l to +l,
Here, m = 0

Answer 6

Spin quantum number (m\(\huge_s\))= +1/2 & -1/2

Answer 7

Now can u solve the original question ur self ?
n=2 is given to u, find out l

Answer 8

is it 3?

Answer 9

@Abhisar

Answer 10

For n=2,
There are 0 to (2-1) possible values

Answer 11

i.e 0 and 1

Answer 12

0 stands for s subshell and 1 stands for p subshell

Answer 13

2s and 2p are the exact subshells possible

Answer 14

getting it ?

Answer 15

or i confused u ?

Answer 16

Sorry I really get it

Answer 17

Sure ?

Answer 18

no sorry I really don't get it is what i meant lol

Answer 19

ohkay all ryt

Answer 20

Lets do it once again

Answer 21

U know shell and subshell ?

Answer 22

no

Answer 23

U know principal quantum number ??

Answer 24

yea

Answer 25

1,2,3,4,5....so on..ryt ?

Answer 26

yes

Answer 27

U know s,p,d,f ??

Answer 28

yep

Answer 29

Fine that's all we need

Answer 30

now principal quantum number (n) represents the shells (1,2,3,4) and Azimuthal quantum number (l) represents the subshells (s,p,d,f).

Answer 31

got this ?

Answer 32

yes

Answer 33

There can be 0 to (n-1) azimuthal quantum numbers (l) for a given principal quantum number n

Answer 34

is that like a formula?

Answer 35

suppose n=2, then there can be 0 to 2-1 azimuthal quantum numbers i.e 0 & 1

Answer 36

ok

Answer 37

if l is equal to
0------->s
1------->p
2------->d
3------->f

Answer 38

got it ?

Answer 39

yes its a formula

Answer 40

so s and p are it

Answer 41

Bingo !!

Answer 42

yay but out of the answer choices 2, 3, 5, 6 how do you determine which one it is

Answer 43

0(s) and 1(p) are the two possible values

Answer 44

Question asks the number of values...so correct option is 2..getting it ?

Answer 45

okay yes I got it thank you soooo much!

Answer 46

Tell me the possible values for n=3

Answer 47

Can u ?

Answer 48

ok hold on

Answer 49

0(s) and 2(d) but wouldn't the answer always have 2 possible answers?

Answer 50

@Abhisar

Answer 51

wrong !

Answer 52

0 to (3-1) this means 0,1 & 2

Answer 53

wait why it is it 0,1,2

Answer 54

@Abhisar

Answer 55

l= 0 to (n-1)

Answer 56

for n=3, 3-1=2 so 0, 1 & 2

Answer 57

ok

Answer 58

u know s,p,d,f configuration of element ?

Answer 59

no ?

Answer 60

yes it do

Answer 61

I*

Answer 62

Then u must have observed there are only 2s & 2p, but there is 3s, 3p & 3d

Answer 63

oh i don't understand it deeply but like i do know what it is

Answer 64

great..lets conclude it

Answer 65

tell me all possible l for n=5

Answer 66

0 to (5-1)
0=1
5-1=4
and 0
so it is 0, 4, 1

Answer 67

where is 2,3 ?

Answer 68

0 to (5-1) i.e 0,1,2,3 & 4

Answer 69

oooo

Answer 70

i didn't know we where to add those

Answer 71

just count...don't add

Answer 72

ok

Answer 73

Tell me for n=6

Answer 74

0 to (6-1)
0=1
and 0
i.e is 0,1,2,3,4,5

Answer 75

what is 0=1 ?

Answer 76

no sorry that was a mistake

Answer 77

n=7

Answer 78

come on last one

Answer 79

i.e is 0,1,2,3,4,5,6
wait how do you determine the s,p,d,f configuration if there is only up to 6 i.e numbers?

Answer 80

no they can be infinite theoretically

Answer 81

But u will hardly learn after 7

Answer 82

and subshells after f

Answer 83

o what are subshells

Answer 84

s,p,d & f are subshells

Answer 85

oh

Answer 86

okay I got it thanks :)

Answer 87

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Answer 88

:)))