Question

Trigonometry Question

Answer 1

What's the question?

Answer 2

\[\tan \Theta+\cot \theta/\sec \Theta+\csc \theta \]

Answer 3

Prove identity to be equal to 1/sin(theta)+cos(theta)

Answer 4

Ask yourself what tangent is.
Then perform the same identification process for cotangent, secant, and cosecant.
The answer will make itself clear.

Answer 5

the two sides are not equal.

Answer 6

\[\tan \theta=\sin \theta/\cos \theta, \cot =1/\tan \theta= \cos \theta /\sin \theta\]

Answer 7

Let's call theda x. It will be easier for to type.

Answer 8

tanx = sinx / cosx
Right?

Answer 9

\[\sec \theta=1/\cos \theta, \csc =1/\sin \theta \]

Answer 10

Exactly. What about cot?

Answer 11

okay let it be x

Answer 12

let theta be x
sinx/cosx+cosx/sinx/1/cos+1/sinx
cosines and sines at the numerator are cancelled out

Answer 13

perform a cross multiplication
1/sinx+cosx/sinxcosx

Answer 14

You skipped some steps, but I think you got the idea.

Answer 15

@lordsampigans How can i get rid of sinxcosx then?

Answer 16

Let me put it this way.... Gimme a second.

Answer 17

So let's look at this as a giant algebra problem with some crazy fractions.

Answer 18

Let's start by asking you a very fundamental question. Sin^2(x) + Cos^2(x) = ?

Answer 19

1

Answer 20

Absolutely. You are now prepared to solve this guy.

Answer 21

So looking at the problem. We have tan(x) + cot(x) all over sec(x) + csc(x)

Answer 22

i got it

Answer 23

Rewrite this. This is confusing to look at. Let's write it as tan(x) + cot(x) / (sec(x) +csc(x)
Literally write your division symbol like you did in grade school.

Answer 24

now thank you

Answer 25

you gave me the hint to solve the problem

Answer 26

Lol. Glad I could help.

Answer 27

Thank you man :)