Question

s=u+1/2at^2......2
s=1/2(u+v)t.......3
v^2=u^2+2as....4
@Somy

Answer 1

so i have to get these formulas?

Answer 2

yes

Answer 3

The first 1 is like this:
From a=v-u/t
at=v-u
v=u+at........1

Answer 4

ok gimme let me try

Answer 5

that's too hard hhh

Answer 6

you did not learn this before?

Answer 7

i do know these formulas
but we did not learn derivation

Answer 8

Okay,nvm..

Answer 9

sorry T_T

Answer 10

It's okay
I'll try to figure it out....

Answer 11

oh
lol
found it

Answer 12

loool ok

Answer 13

(v+u)/2 --- average velocity formula

S= v*t
thus

\[s= \frac{ v+u }{ 2 }\times t\]

Answer 14

that's for s=1/2(u+v)t.......3

Answer 15

now for this
s= ut+ 1/2at^2

Answer 16

\[v= u + at\]
\[s= \frac{ u+v }{ 2 }\times t\]
we use these 2 formulas
now we substitute v in second equation by first equation
\[s= (\frac{ u+u+at }{2}) \times t\]
now simplify
\[s= \frac{ 2ut }{ 2 } +\frac{ at^2 }{ 2 }\]

thus
\[s= ut +\frac{ 1 }{ 2 } at^2\]

Answer 17

now next one
\[v= u+at \]
\[s= \frac{ u+v }{ 2 } \times t\]
again we use these formulas

lets make t as subject in first equation
\[t= \frac{ v-u }{ a }\]

now lets substitute t in \[s= \frac{ u+v }{ 2 } \times t\]
by the t we just made as subject
\[s= \frac{ u+v }{ 2 } \times \frac{ v-u }{ a }\]

rearranging this
\[2as= (u+v)(v-u) \]
\[2as= v^2-u^2 \]

make v^2 as subject
\[v^2= u^2 +2as\]

Answer 18

done :) any questions?

Answer 19

Nope

Answer 20

Thanks @Somy

Answer 21

you are welcome :)))