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Chemistry 22 Online
OpenStudy (anonymous):

Using the formula qmetal = m × c × ΔT, calculate the specific heat of the metal. Use the data from your experiment for the metal in your calculation.

OpenStudy (anonymous):

@thushananth01 would I be solving for ΔT here?

OpenStudy (anonymous):

@Somy can you help me? :3

OpenStudy (anonymous):

OpenStudy (somy):

nope, you need to find specific heat capacity here

OpenStudy (anonymous):

how would I do that?

OpenStudy (somy):

alright

OpenStudy (somy):

could you write all the info from pic ?

OpenStudy (anonymous):

Yeah; the measured mass of the metal is 27.776 g, distilled water is 26 mL, distilled water temperature is 25.3 c, temperature of metal is 100.6 c, temperature of the mixture is 38.9 c

OpenStudy (somy):

alright look when it comes to formula Q= mc Delta T only values you care about are about water

OpenStudy (somy):

in this case i mean

OpenStudy (anonymous):

so distilled water is 26 mL, distilled water temperature is 25.3 c

OpenStudy (somy):

yes and temp of mixture?

OpenStudy (anonymous):

38.9 c

OpenStudy (somy):

do consider this one because that metal is with water and because metal had some temperature which raised waters temp after putting it water

OpenStudy (somy):

so now we actually will find Q

OpenStudy (somy):

Specific heat capacity of water is 4.18

OpenStudy (anonymous):

would I set it up like this: \[q= 26 * 4.18 (38.9 - 25.3)\]

OpenStudy (somy):

yeah

OpenStudy (anonymous):

and q is 1442?

OpenStudy (somy):

no, its close but u made mistake in some number

OpenStudy (somy):

it'll be 1478.048

OpenStudy (somy):

or we can say 1478 J

OpenStudy (anonymous):

where did I make the mistake?

OpenStudy (anonymous):

never mind I checked my calculations

OpenStudy (somy):

ok) now lets move on

OpenStudy (somy):

now we have value for Q and now we are going to consider metal

OpenStudy (somy):

what is metal's mass? and Delta T

OpenStudy (anonymous):

ok so it would be q= 27.776 x 4.18 x (100.6 - 38.9) ??

OpenStudy (somy):

no no specific hear capacity is what we need to find

OpenStudy (somy):

Q is what we found in the other part

OpenStudy (somy):

heat*

OpenStudy (anonymous):

oh okay so we use q that we found ok sorry

OpenStudy (somy):

1478 J = 27.776* X* (100.6-38.9)

OpenStudy (somy):

yes thats right :) because the question is asking for specific heat capacity of metal

OpenStudy (somy):

is it clear?

OpenStudy (anonymous):

yes! i'm doing the calculations now

OpenStudy (somy):

good :))

OpenStudy (anonymous):

i got 1.16? :x

OpenStudy (somy):

let me check if something is wrong with my calculator ok?

OpenStudy (anonymous):

i did 1713 by 1478 instead of 1478 by 1713

OpenStudy (somy):

no no

OpenStudy (somy):

it should be 1478/1713

OpenStudy (anonymous):

ok then sorry its .8628

OpenStudy (somy):

yeah :)

OpenStudy (anonymous):

thank you so much you're the best!

OpenStudy (somy):

hehe you are welcome :))♥♥♥

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