Mathematics
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OpenStudy (anonymous):
how to solve f(x)=x^2-3x-2
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OpenStudy (anonymous):
will u elaborate
OpenStudy (zzr0ck3r):
there is nothing to solve
OpenStudy (zzr0ck3r):
you may solve x^2-3x-2=0
or you may find the zeros of f(x)
but solving f(x) makes no sense.
OpenStudy (anonymous):
given the function rule f(x)= x^2 -3x+2, what is the out put of f(-2)
OpenStudy (anonymous):
12
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OpenStudy (anonymous):
i need to know how did u do it
OpenStudy (anonymous):
not the awenser
OpenStudy (zzr0ck3r):
put a -2 where you see an x
\(f(x) = x^2-3x-2\\f(-2) = (-2)^2-3(-2)-2 = 4+6-2=8\)
OpenStudy (anonymous):
THANK YOU SO MUCH!!!!
OpenStudy (anonymous):
-2^2 -3(-2)+2=12 @zzr0ck3r
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OpenStudy (zzr0ck3r):
its not -2^2 its (-2)^2
OpenStudy (zzr0ck3r):
-2*-2 = 4
OpenStudy (zzr0ck3r):
one must be careful when plugging in cvalues, I always use the () as I did ablove as not to confuse myself...
OpenStudy (zzr0ck3r):
values*
OpenStudy (zzr0ck3r):
@jaga_co understand?
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OpenStudy (anonymous):
so who is right?
OpenStudy (anonymous):
before give ans see the problem
OpenStudy (anonymous):
given the function rule f(x)= x^2 -3x+2, what is the out put of f(-2) @zzr0ck3r
OpenStudy (zzr0ck3r):
I am right. I promise
OpenStudy (anonymous):
i know for a fackt that the awense is 12 but i dont know how to work it out
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OpenStudy (anonymous):
fact*
OpenStudy (zzr0ck3r):
that topic says -2
OpenStudy (zzr0ck3r):
f(x)=x^2-3x-2
OpenStudy (zzr0ck3r):
I am confused
OpenStudy (zzr0ck3r):
OHHHHHHHH lol you changed the equation
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OpenStudy (zzr0ck3r):
sorry
OpenStudy (anonymous):
thanks @zzr0ck3r for your confusion
OpenStudy (zzr0ck3r):
@jaga_co is correct
OpenStudy (anonymous):
lol its kk :)
OpenStudy (zzr0ck3r):
notice the thing in the topic is not the same thing as in the follow up
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OpenStudy (anonymous):
i wish i could give u boath a medal but i have to give it to jaga_co :)
OpenStudy (zzr0ck3r):
lol I dont need medals:)
OpenStudy (zzr0ck3r):
I medal-ed him also:)
OpenStudy (anonymous):
kk :) thanks aney way