Question

rewrite the expression

(1/1-sinx)-(sinx/1+sinx)

Answer 1

\[\frac{ 1 }{ 1-\sin x }-\frac{ \sin x }{ 1+\sin x } \]
=\[\frac{ 1+\sin x-\sin x(1-\sin x) }{ 1-\sin ^2x }\]
=\[\frac{ 1+\sin x-\sin x+\sin ^2x }{ \cos ^2x }=\frac{ 1+\sin ^2x }{ \cos ^2x }=\frac{ -\cos ^2x }{ \cos ^2x }\]
=-1

Answer 2

thank you