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The total number of fungal spores can be found using an infinite geometric series where a1 = 11 and the common ratio is 2. Find the sum of this infinite series that will be the upper limit of the fungal spores.
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@amistre64
geometric infinite sum =a1/(1+r)
yah but idk how to set it up
11/3?
" where a1 = 11 and the common ratio is 2" so a1 = 11 and r = 2
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11/3? yes!
then what :)
"Find the sum of this infinite series that will be the upper limit of the fungal spores." the answer is 11/3
these are the options... 465 280 The series is divergent 125
oh wait, sorry! i see what I did wrong
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if |r|<1, then geometric infinite sum =a1/(1+r) else the series is divergent
oh ok thank you
^_^
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