Question

Given the geometric sequence where a1 = 4 and the common ratio is 3, what is the domain for n?

For this its always greater than one right? for every type of these things?

Answer 1

These are the options

All integers where n ≥ 1

All integers where > 1

All integers where n ≥ 4

All real numbers

Answer 2

since r is greater than 1, that means integers greater than or equal to 1.

it can't be all real numbers, becuase that would include negative nubmers

Answer 3

ok so greater than or equal to 1


also Given the arithmetic sequence an = 4 − 3(n − 1), what is the domain for n?

All integers where n ≥ 1

All integers where n > 1

All integers where n ≤ 4

All integers where n ≥ 4


this is the last one

Answer 4

same idea as the prior question

Answer 5

so is it always greater than or equal to?

Answer 6

if the starting number of a sequnce is 4, if we put n=0, then we get 4, but if we put in a negative n, we would get a value that isn't part of our sequence, so it has to be n is greater than or equal to 1

Answer 7

ohhhh ok thank you!!

Answer 8

" if we put n=0, th"
if we put n=1, th
sorry!

Answer 9

^_^