SAME PROBLEM NEW QUESTION: An object with total mass mtotal = 15.3 kg is sitting at rest when it explodes into three pieces. One piece with mass m1 = 4.9 kg moves up and to the left at an angle of θ1 = 20° above the –x axis with a speed of v1 = 25.6 m/s. A second piece with mass m2 = 5.3 kg moves down and to the right an angle of θ2 = 25° to the right of the -y axis at a speed of v2 = 23 m/s. What is the y-component of the velocity of the third piece? Is it the same process just substituting sin for cos? https://www.smartphysics.com/Content/smartPhysics/Media/Images/Mechanics/13/explosion3.png
vector (p) = vector (p1) + vector (p2) + vector (p3) = 0 =4.9*25.6*cos 160 +5.3*23*cos -65 +5.1*v3*cosθ3 The x component is the v3*cosθ3 :D
May I ask how you came up with the angles, I am a bit confused.
http://www.mathsisfun.com/geometry/images/circle-unit-sct.gif On a unit circle, the angle is calculated as from the Ox, counter-clockwise to the vector we need. The x component as you can see, is calculated as cosθ So if you have θ1 = 20°, the angle we need to find is 180 - 20. θ2 = 25° like that, the angle should be 90 - 25. When you have the angle, times it with the length of the vector. It's trigonometry :D
Okay that make sense You have to cal
*calculate from the same point for both angles
:D
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