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How do I find the domain of (f*g)(x) for each f(x) and g(x): f(x)=√x-2 g(x)= (1) / (4x) and get x≤ 1/8?
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\[f(x)=\sqrt{x-2}\] since you cannot take the square root of a negative number find the domain via \[x-2\geq 0\] or \[x\geq 2\]
is \[g(x)=\frac{1}{4x}\]?
also, is it ] \[f\times g(x)\] or \[f\circ g(x)\]?
the second one. f∘g(x)
@satellite73
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Basically its asking you for \[f(g(x))\] .
ooh ok that makes more sense
\[\large f\circ g(x)=f(g(x))=f(\frac{1}{4x})=\sqrt{\frac{1}{4x}-2}\]
since you cannot take the square root of a negative number, your job is to solve \[\frac{1}{4x}-2\geq 0\]
you know how to do that?
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yes
ok good you should get \[0<x\leq \frac{1}{8}\]
yup thats what i got! thanks!
yw
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