write the equations in slope intercept and standard form: parallel to y= -5 and through (2,7) vertical and contains (-4,6) x-intercept= 2 and y-intercept= -4
To start, are you familiar with point-slope film?
@Amenah8
\[y-y _{1}=m(x-x _{1})\]
where m is your slope, x1 is your x coordinate, and y1 is your y coordinate
are you able to see this graph?
if not then i can draw it for you here.
if you can see it, or even from the information of y = -5, would you be able to tell me the slope of that line?
i see it. one moment, let me figure out the slope
is slope 0??
yes good. the slope here is 0
so you know that at any x point, the y will be -5 for that graph. Try to think how you could make another line parallel (same slope) to your original line where your line goes through (2, 7)
slope would still be 0. so the parallel line would be going through (0,7) and one of the points would then be (2,7).
and so slope intercept form is y=0x+7??
yes perfect! so now because you have 0x you can kind of just get rid of that part
so just y=x+7??
no, because then x has a value. in 0x, no matter what x will be your equation will end up being 0+7 because 0 times anything is still 0
so look back to y = -5. there is no x there because there is no slope. how can you do that with this equation?
y=7
perfect :)
and i can be corrected if i am wrong but i do not believe there is a way to convert that into standard form because it is already in standard form
yes perfect
thank you so much!!
alright, next part. so, we just did an equation where the line is horizontal. and it was y = -5. now we are looking for a line that is vertical. can you guess what we will change in out equation?
*our
you would have the x intercept instead of the y intercept
yes exactly, knowing that youre now dealing with x, how can you have a line that goes vertically through (-4, 6)?
x intercept is -4
yes. so take the y = -5. how can you write this problem like that?
does a vertical line have no slope?
would it be x= -4?
yes it would good job
so that is slope intercept and standard form
yes it is
alright now, could you see the last graph i sent a link for?
for y= -5? yes
alright i'm going to send you another link and walk you through it ok?
ok
https://www.desmos.com/calculator/nmg7iheud6 alright, on this graph you should see 2 points that will make up your line
the x-intercept and the y-intercept that you were given in your problem
do you see that?
yes
cool ok now, i would recommend, if you havent already done this, to scroll in until you see your graph going up by one every line so on the x-axis it should be 1, 2, 3, 4 each line instead of by 2s or 5s
i only recommend this because it should be easier to visualize that way
okay, i have it
alright so do you know that slope is another way of saying "rise over run"?
yes
so -4 over 2?
in this case it would not be -4 but you are almost right
your (0, -4) point is farther to the left from your (2, 0) point meaning that you are going from a lower number to a higher number. this means your slope is positive
knowing that how do you put the rise over run part?
4 over 2?
perfect and 4/2 =?
2
that is your slope
so y=2x+-4 for slope intercept form
yes and that can be written as y= 2x - 4
right. and standard form is -2x+y= -4 right? or is A not allowed to be negative?
no, you are correct good job :)
Thank you so much. this really helped me a lot :)
good im glad. you can tag me if you have any more questions you need help on
ok, thanks again
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