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Chemistry 15 Online
OpenStudy (superhelp101):

Which of the following quantum number combinations is not allowed in an atom? n= 2, l= 1, m= 0 n= 1, l= 0, m= 0 n= 4, l= 3, m= -3 n= 2, l = 3, m= 2

OpenStudy (superhelp101):

so for this one is it the first option @chmvijay

OpenStudy (superhelp101):

@ParthKohli

Parth (parthkohli):

Do you know the rules for all quantum numbers? \(n\) is a positive integer, meaning that \(n = 1, 2, 3\cdots\). \(l\) is always a positive integer less than \(n\) meaning that \(l = 1,2,3~\cdots~n-1\). \(m\) ranges from \(-l\) to \(l\).

OpenStudy (superhelp101):

oh so it should be the first option correct?

Parth (parthkohli):

How did you get that?

OpenStudy (superhelp101):

I did exactly what you explain earlier

Parth (parthkohli):

Can you explain further?

OpenStudy (superhelp101):

i just plugged in 2 for 0 to (n-1) so 0 to 1.

OpenStudy (superhelp101):

i am just going to go with the first choice

Parth (parthkohli):

Do you know the fact that \(l\) is less than \(n\)?

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