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Which of the following quantum number combinations is not allowed in an atom? n= 2, l= 1, m= 0 n= 1, l= 0, m= 0 n= 4, l= 3, m= -3 n= 2, l = 3, m= 2
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so for this one is it the first option @chmvijay
@ParthKohli
Do you know the rules for all quantum numbers? \(n\) is a positive integer, meaning that \(n = 1, 2, 3\cdots\). \(l\) is always a positive integer less than \(n\) meaning that \(l = 1,2,3~\cdots~n-1\). \(m\) ranges from \(-l\) to \(l\).
oh so it should be the first option correct?
How did you get that?
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I did exactly what you explain earlier
Can you explain further?
i just plugged in 2 for 0 to (n-1) so 0 to 1.
i am just going to go with the first choice
Do you know the fact that \(l\) is less than \(n\)?
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