Ask your own question, for FREE!
Mathematics 16 Online
OpenStudy (anonymous):

If x is the smallest integer factor of 3^200 + 5^200 other than 1, what is the value of x? A. 2 B. 3 C. 5 D. 8 E. 15 can someone explain to me how to get the answer?

ganeshie8 (ganeshie8):

Have you tried anything yet ?

OpenStudy (anonymous):

uhh i dont know where to start

ganeshie8 (ganeshie8):

may be lets try first option

ganeshie8 (ganeshie8):

whats the remainder when 3 is divided by 2 ?

OpenStudy (anonymous):

1

ganeshie8 (ganeshie8):

Yes, 3 leaves a remainder of 1 when divided by 2 so, 3^200 leaves a remainder of 1^200 when divided by 2

ganeshie8 (ganeshie8):

1^200 is same as 1 so 3^200 leaves a remainder of 1 when divided by 2

OpenStudy (anonymous):

ohh i see

ganeshie8 (ganeshie8):

next work out the remainder of 5^200 when divided by 2

OpenStudy (anonymous):

and it has to work for both values so that is the lowest one

OpenStudy (anonymous):

3

ganeshie8 (ganeshie8):

whats the remainder when 5 is divided by 2 ?

OpenStudy (anonymous):

3

ganeshie8 (ganeshie8):

think again

OpenStudy (anonymous):

1

OpenStudy (anonymous):

oops

ganeshie8 (ganeshie8):

:) since 5 leaves a remainder of 1 when divided by 2, 5^200 leaves a remainder of 1^200 when divided by 2

ganeshie8 (ganeshie8):

Overall : 3^200 + 5^200 leaves a remainder of 1+1 = 2 when divided by 2

ganeshie8 (ganeshie8):

but 2 is same as 0 when speaking about remainders so 2 is the smallest integer factor

OpenStudy (anonymous):

ahh okay

OpenStudy (anonymous):

@ganeshie8 is right! but may i also say that no matter how many times you multiply odd numbers, that stay odd. so 3^200 is odd, so is 5^200. when you add then, that's even, i.e. divisible by 2 this particular problem can be solved in this way too :)

ganeshie8 (ganeshie8):

thats a very good observation and looks neat !

OpenStudy (anonymous):

ahh okay

OpenStudy (anonymous):

thanks!

ganeshie8 (ganeshie8):

yw :) are you doing number theory ?

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!