Question

A country's population in 1993 was 127 million.

In 2000 it was 132 million. Estimate
the population in 2008 using the exponential
growth formula. Round your answer to the
nearest million.

P = Aekt
Now solve for k

Answer 1

@Pizza7

Answer 2

Use 1993 as year 0 and 127million as your starting point, thus your equation starts as

P=127e^(k*0)

since e^0 =1 that's 127milion just as it should be, next set it equal to 132mil and change the t to 7 years

132=127e^(k*7) now solve for k, first divide both sides by 127

132/127 = e^(k*7) next take the natural log of both sides leaving

ln(132/127) = k*7 finally divide both sides by 7

k = (ln(132/127))/7

The result k= 0.005516405 rounded to 4 decimal places k= .0055

now put that in the equation and set the time to 15 years for 2008

P= 127e^(.0055*15) =137.9218 to the nearest million... 138 million people in 2008

hope that helps

Answer 3

The result k= 0.005516405

Answer 4

Yep thanks :)

Answer 5

welcome