Question

Find the slope of the line through the pair of points A(2,-3), P(2,9)

can someone help please. thank you.

Answer 1

\(\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
A&({\color{red}{ 2}}\quad ,&{\color{blue}{ -3}})\quad B&({\color{red}{ 2}}\quad ,&{\color{blue}{ 9}})
\end{array}
\\\quad \\

slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies \cfrac{{\color{blue}{ y_2}}-{\color{blue}{ y_1}}}{{\color{red}{ x_2}}-{\color{red}{ x_1}}}\)

Answer 2

use that same result for these too..
m=\[\frac{ (y2-y1) }{ (x2-x1) }\]
here x1=x2=2,y1=-3,y2=9

Answer 3

I subtract both of them then?

Answer 4

1/0?

Answer 5

slope(m) = (y2 - y1) / (x2 - x1)
(2,-3)..x1 = 2 and y1 = -3
(2,9)...x2 = 2 and y2 = 9
now sub
slope(m) = (9 - (-3) / (2 - 2)
slope(m) = (9 + 3) / 0
slope(m) = 12/0

When the denominator is 0, then the line is a vertical line with an undefined slope.
IF the numerator would have been 0, then the line would have been horizontal with a slope of 0.

Answer 6

Gotcha!!! thank you.

Answer 7

sure thing :)