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Mathematics 7 Online
OpenStudy (moka414):

write a rule for the linear function in the table. Please can someone help me understand?

OpenStudy (moka414):

OpenStudy (jdoe0001):

is a "linear function" meaning, it makes a line so let us pick 2 points from the table first, say the 1st and last keep in mind that we could really pick any two points off the set \( \begin{array}{ccllll} x&y \\\hline\\ \underline{-4}&\underline{16}\\ 0&0\\ 4&-16\\ \underline{8}&-\underline{32} \end{array} \\ \quad \\ \bf \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ &({\color{red}{ -4}}\quad ,&{\color{blue}{ 16}})\quad &({\color{red}{ 8}}\quad ,&{\color{blue}{ -32}}) \end{array} \\\quad \\ slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies \cfrac{{\color{blue}{ y_2}}-{\color{blue}{ y_1}}}{{\color{red}{ x_2}}-{\color{red}{ x_1}}} \\ \quad \\ y-{\color{blue}{ y_1}}={\color{green}{ m}}(x-{\color{red}{ x_1}})\qquad \textit{plug in the values and solve for "y"}\\ \qquad \uparrow\\ \textit{point-slope form}\)

OpenStudy (jdoe0001):

so you'd get the slope, and plug in your values in the "point-slope form" then you can solve it for "y" if you need it in slope-intercept form if you do not, they you can leave it like so, in point-slope form too

OpenStudy (phi):

do you understand what jdoe posted? they want you to find the equation of line that goes through those points do you know how to find the equation of a line?

OpenStudy (moka414):

Oh okay let me try it

OpenStudy (phi):

pick two points and find the slope between those two points I would use (0,0) as one of the points (easy math)

OpenStudy (phi):

For future reference, here is a video about slope http://www.khanacademy.org/math/algebra/linear-equations-and-inequalitie/slope-and-intercepts/v/slope-of-a-line

OpenStudy (moka414):

I got 12/36

OpenStudy (phi):

what two points did you use?

OpenStudy (moka414):

I used -2/5 then 3/3

OpenStudy (moka414):

wait i got it mix up

OpenStudy (moka414):

-4-8 = 12 then the second one is 16-32=36 then I divided into 2where it came out to 6/16

OpenStudy (moka414):

is that correct or am I missing something?

OpenStudy (phi):

so you used the first point (-4,16) and the last point (8,-32) the x values are the first number in each pair. the y values are the second number in each pair. change in y is 16 - (-32) change in x is -4 - 8 can you simplify those?

OpenStudy (phi):

you could use a calculator if you have one.

OpenStudy (moka414):

Okay let me try

OpenStudy (moka414):

48/12 simplify that?

OpenStudy (phi):

almost. -4 - 8 is not +12 try again

OpenStudy (moka414):

so is minus?

OpenStudy (phi):

yes. try it with a calculator (but I would learn how to do negative numbers!) you get 48/-12 which simplifies to -4

OpenStudy (moka414):

oh okay how would I used the negative on the calculator let me check on that link

OpenStudy (moka414):

so the answer fCX) -4x?

OpenStudy (phi):

f(x)= -4x the way you get that is to know the equation of a line is f(x) = mx + b where m is the slope (some number) and b is the y-intercept. we found the slope to be -4, (i.e. m= -4) so we know (so far) f(x)= -4x + b to find b, we pick a point that is on the line (in the table) I would pick (0,0) (but any pair will work) replace x with 0, and replace f(x) with 0 in our equation to get 0 = -4*0 + b simplify : 0= 0+b b+0 is b (adding 0 to anything , even a letter, does not change it) we get 0 = b so we know b is 0 and the equation is f(x)= -4 x + 0 but we never bother to write +0 , so we just write f(x)= -4 x

OpenStudy (moka414):

thank you so much!!!!!

OpenStudy (phi):

yw

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