Question

What are the solutions of the quadratic equation below?

2x2 - 2x - 9 = 0?

it has to be a fraction please help.

Answer 1

I dont remember this right now but this may help. http://www.wolframalpha.com/input/?i=quadratic+answers+in+fractions+2x2++-++2x++-++9++%3D++0%3F+

Answer 2

well you need to general quadratic formula so the roots are real and irrational... after checking by using the discriminant

Answer 3

A Quadratic Equation\[ax^2+bx+c=0\]
The Quadratic Formula\[x_{1,2}=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\]


Start by identifying the coefficients \(a\), \(b\), \(c\)
Compare
\[2x^2 - 2x - 9 = 0\]With
\[ax^2+bx+c=0\]
\[a=?\\
b=?\\
c=?\]

Answer 4

Can you identify the coefficients @Soccergirl52 ?

Answer 5

i cannot :C its too hard >.<

Answer 6

Compare
\[\color{orange}2x^2+\color{salmon}{−2}x+\color{cornflowerblue}{−9}=0\]With
\[\color{orange}ax^2+\color{salmon}bx+\color{cornflowerblue}c=0\]

\[\color{orange}a=?\\\color{salmon}b=?\\\color{cornflowerblue}c=?\]

Answer 7

let me see..

Answer 8

its hard >.< :*(

Answer 9

x=(-b±√b^2-4ac)/2a
x=(2±√4+72) /4
x=(1±√19)/2

Answer 10

UnkleRhaukus has explained everything required......
First learn the basics like finding the coefficients.....
Then it is very easy.... :)