7. The isotope cesium-137, which has a half-life of 30 years, is a product of nuclear power plants. How long will it take for this isotope to decay to about one-half of its original amount?
(a) 0 years
(b) 15 years
(c) 30 years
(d) 60 years
@Abhisar @UnkleRhaukus
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OpenStudy (anonymous):
So with the formula is B?
OpenStudy (unklerhaukus):
The half-life of a substance is the time it takes for half of it to decay
OpenStudy (abhisar):
\(\huge\frac{1}{2}\) = \(\huge\frac{1}{2^n}\)
OpenStudy (abhisar):
n represents the number of times half time has elapsed.
OpenStudy (anonymous):
so the answer is 15?
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OpenStudy (abhisar):
So by solving the above equation u get n= ??
OpenStudy (anonymous):
is n 30 or 137?
because if it is 137 then the answer is 68.5
OpenStudy (anonymous):
but if n is 30 the answer is 15
OpenStudy (abhisar):
n = 1
OpenStudy (anonymous):
huh?
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OpenStudy (anonymous):
1/2^1?
OpenStudy (abhisar):
1/2^1 = 1/2
OpenStudy (abhisar):
So, n=1
OpenStudy (anonymous):
\[\frac{ 1 }{ 2^1 }\]
OpenStudy (abhisar):
this means half life has elapsed once
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OpenStudy (abhisar):
Therefore 30 years have elapsed.
OpenStudy (abhisar):
getting my points ?
OpenStudy (anonymous):
no
OpenStudy (anonymous):
so the answer is C?
OpenStudy (anonymous):
so the answer is in the question
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OpenStudy (anonymous):
i don't get how you get the half life of 30 years
OpenStudy (abhisar):
ok wait..brb
OpenStudy (anonymous):
brb
OpenStudy (unklerhaukus):
The question states the isotope has a half-life of 30 years
OpenStudy (abhisar):
The question says that half life of isotope is 30 years
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OpenStudy (abhisar):
Now, let the number of times half life (30 years) has elapsed be n. Then total time elapsed will be 30n
OpenStudy (abhisar):
Formula for finding the fraction of isotope left is \(\huge\frac{1}{2^n}\)
OpenStudy (anonymous):
ok
OpenStudy (abhisar):
Question says that \(\huge\frac{1}{2}\) is left.
OpenStudy (anonymous):
which would make the answer 68.5 or 15 years
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OpenStudy (abhisar):
This implies that \(\huge\frac{1}{2^n}\)=\(\huge\frac{1}{2}\)
OpenStudy (abhisar):
So n=1
OpenStudy (abhisar):
Therefore total time elapsed = 30*1=30 years
OpenStudy (abhisar):
got it ?
OpenStudy (anonymous):
why is in N=1
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OpenStudy (abhisar):
Solve the equation
\(\color{blue}{\text{Originally Posted by}}\) @Abhisar
This implies that \(\huge\frac{1}{2^n}\)=\(\huge\frac{1}{2}\)
\(\color{blue}{\text{End of Quote}}\)
OpenStudy (anonymous):
i don't get why or how N=1
OpenStudy (abhisar):
u know how to solve equations ?
OpenStudy (abhisar):
ok leave all
OpenStudy (abhisar):
Lets do it conceptually
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OpenStudy (anonymous):
ok
OpenStudy (abhisar):
\(\color{blue}{\text{Originally Posted by}}\) @UnkleRhaukus
The half-life of a substance is the time it takes for half of it to decay
\(\color{blue}{\text{End of Quote}}\)
OpenStudy (abhisar):
Now the question says that only 1/2 is left i.e half is left and half is decayed
OpenStudy (anonymous):
ok
OpenStudy (unklerhaukus):
|dw:1403961417013:dw|
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