Mathematics
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OpenStudy (anonymous):
Find the derivative of f(x) = 8 divided by x at x = -1.
11 years ago
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OpenStudy (anonymous):
@ganeshie8 @robtobey if you could assit me i would appreciate your help.
11 years ago
ganeshie8 (ganeshie8):
familiar with any formulas ?
11 years ago
OpenStudy (anonymous):
would you have to do the difference quotient formula
11 years ago
ganeshie8 (ganeshie8):
yes, can you show me the formula which you have ?
11 years ago
OpenStudy (anonymous):
f(x+h)-f(x)/h
11 years ago
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OpenStudy (anonymous):
this is where i dont know how to proceed
11 years ago
ganeshie8 (ganeshie8):
what about the limit ?
11 years ago
ganeshie8 (ganeshie8):
\[\large f'(x) = \lim \limits_{h\to 0} \dfrac{f(x+h) - f(x)}{h}\]
11 years ago
OpenStudy (anonymous):
the limit is -1 in the formula its limit h to 0=f(x+h)-f(x)/h
11 years ago
ganeshie8 (ganeshie8):
thats the formula right ?
11 years ago
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OpenStudy (anonymous):
yes exactly
11 years ago
ganeshie8 (ganeshie8):
start by finding the difference `f(x+h) - f(x)`
11 years ago
ganeshie8 (ganeshie8):
f(x) = 8/x
f(x+h) = ?
11 years ago
OpenStudy (anonymous):
8(x+h) -8/x
11 years ago
ganeshie8 (ganeshie8):
yes, put them as single fraction by working the common denominator
11 years ago
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OpenStudy (anonymous):
x(8(x+h))-8/x
11 years ago
OpenStudy (anonymous):
8x(x^2+hx)-8/x
11 years ago
ganeshie8 (ganeshie8):
\(\large \dfrac{8}{x+h} - \dfrac{8}{x}\)
11 years ago
ganeshie8 (ganeshie8):
multiply the first fraction by x/x
second fraction by (x+h)/(x+h)
11 years ago
ganeshie8 (ganeshie8):
\(\large \dfrac{x}{x}\dfrac{8}{x+h} - \dfrac{8}{x}\dfrac{x+h}{x+h}\)
11 years ago
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ganeshie8 (ganeshie8):
\(\large \dfrac{8x}{x(x+h)} - \dfrac{8(x+h)}{x(x+h)}\)
11 years ago
ganeshie8 (ganeshie8):
Now that the denominators are same, you can add/subtract the numerators
11 years ago
ganeshie8 (ganeshie8):
\(\large \dfrac{8x - 8(x+h)}{x(x+h)}\)
11 years ago
ganeshie8 (ganeshie8):
simplify
11 years ago
OpenStudy (anonymous):
8h/x^2+hx
11 years ago
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ganeshie8 (ganeshie8):
careful about signs *
11 years ago
OpenStudy (anonymous):
-8h/x^2+hx
11 years ago
ganeshie8 (ganeshie8):
yes, so
f(x+h) - f(x) = -8h/(x^2+hx)
11 years ago
ganeshie8 (ganeshie8):
plug this value in your earlier difference quotient formula
11 years ago
ganeshie8 (ganeshie8):
\[\large f'(x) = \lim \limits_{h\to 0} \dfrac{f(x+h) - f(x)}{h}\]
11 years ago
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ganeshie8 (ganeshie8):
\[\large f'(x) = \lim \limits_{h\to 0} \dfrac{-8h/(x^2+hx)}{h}\]
11 years ago
ganeshie8 (ganeshie8):
h cancels out ^
11 years ago
ganeshie8 (ganeshie8):
\[\large f'(x) = \lim \limits_{h\to 0} -8/(x^2+hx)\]
11 years ago
ganeshie8 (ganeshie8):
Since there is no h in the bottom, you can take the limit now
11 years ago
ganeshie8 (ganeshie8):
simply plugin h = 0
11 years ago
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ganeshie8 (ganeshie8):
\[\large f'(x) = \lim \limits_{h\to 0} -8/(x^2+hx)\]
\[\large f'(x) = -8/(x^2+0 \times x)\]
\[\large f'(x) = -8/x^2\]
11 years ago
ganeshie8 (ganeshie8):
thats the derivative function ^
11 years ago
ganeshie8 (ganeshie8):
plugin x = -1 to get the derivative at x = -1
11 years ago
OpenStudy (anonymous):
would it -8 as your derivative
11 years ago
ganeshie8 (ganeshie8):
Yep !
11 years ago
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OpenStudy (anonymous):
thank you for your help its very kind of you to take the the time and effort to assist me. i appreciate your assistance and i hope you have a nice day.
11 years ago
ganeshie8 (ganeshie8):
np, you're welcome :) good day !
11 years ago