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Trigonometry 18 Online
OpenStudy (anonymous):

Solve the triangle. B = 72°, b = 12, c = 8

OpenStudy (anonymous):

do you know the Law of Sines?

OpenStudy (anonymous):

a/sinA=b/sinB=c/sinB

OpenStudy (dumbcow):

shoot i messed up, the order is wrong

OpenStudy (anonymous):

yes @gloves exactly. now only looking at the b/sinB = c/sinC part, how do you think you could plug in the numbers you are given?

OpenStudy (anonymous):

yea @dumbcow i was going to say i wouldnt recommend the law of cosines here

OpenStudy (anonymous):

12/sin72=8/sinC

OpenStudy (anonymous):

perfect now, can you cross multiply that?

OpenStudy (anonymous):

8(sin72)=12(sinC)

OpenStudy (anonymous):

try multiplying 8 and sin72

OpenStudy (anonymous):

7.6

OpenStudy (anonymous):

yes but you can use the knowledge that a triangle has 180 degrees and subtract

OpenStudy (anonymous):

now divide that number by 12

OpenStudy (dumbcow):

yeah i had a dumb moment

OpenStudy (anonymous):

180-72=108

OpenStudy (anonymous):

and divid 108 by 12?

OpenStudy (anonymous):

divide*

OpenStudy (anonymous):

for now just divide 7.6 by 12. you should get some annoying decimal, but i will make it make sense

OpenStudy (anonymous):

0.633

OpenStudy (anonymous):

alright now do you know that inverse sines are the opposite of sines the way multiplication is the opposite of division?

OpenStudy (anonymous):

yeah

OpenStudy (anonymous):

perfect, then inverse sine your 0.633

OpenStudy (anonymous):

you should get something that may also be a decimal. if so, just round it up to the nearest whole number

OpenStudy (anonymous):

39.27degrees

OpenStudy (anonymous):

i would round that to just 39 degrees

OpenStudy (anonymous):

alright so is that my angle for c

OpenStudy (anonymous):

now you have, 72 degrees as angle B, 39 degrees as angle C, and now we go back to addition and subtraction

OpenStudy (anonymous):

triangle=180 degrees. how do you find angle A?

OpenStudy (anonymous):

69

OpenStudy (anonymous):

180-39-72

OpenStudy (anonymous):

yep perfect now you have angle A. look back to your Law of sines and look now at the a/SinA=b/SinB part how can you plug what you have into that?

OpenStudy (anonymous):

a/sin69=12/sin72

OpenStudy (anonymous):

awesome now for this part id say just multiply the 12 by sin69 as like halfway cross multiplying and the reason for that is then you make this a 1 step problem. 12(sin69)/sin72 = a

OpenStudy (anonymous):

11

OpenStudy (anonymous):

perfect, there you go

OpenStudy (anonymous):

so side a=11 b=12 c=8 A=69, B=72 C=39

OpenStudy (anonymous):

@TechnoSoul thank you so miuch for your help

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