Question

The vertex of the function’s graph is given. Find c.
y = x2 + 10x + c; (-5, -27)

Answer 1

There are several versions of the equation of a parabola (which is what you have here).
One of them is the standard form y=ax^2 + bx + c. That's the form your y = x2 + 10x + c has. the other is the vertex form: \[y=x(x-h)^2+k,\]where (h,k) is the vertex (a point).

Answer 2

for the same parabola, these two equations should give you one and the same graph.

Thus: You could equate your y = x2 + 10x + c to the vertex form of the equation:

y = x2 + 10x + c = a(x-h)^2+k.

Important: Please do not write 'x2' for 'the square of x.' Instead, write x^2 or \[x ^{2}\]

Answer 3

What is h? What is k? what's left to find?

Answer 4

what?

Answer 5

Your job is to find the value of c in \[y=x^2+10x+c.\]Where do you think that "c" value is going to come from?
Why do you think I mentioned the "vertex form of the equation of a parabola?"

Answer 6

Sorry. We were on the verge of answering this problem. OpenStudy tells me you're looking at some other problem now. If you're back within 2 minutes, I'd be glad to help you finish the problem at hand.

Answer 7

i just guessed because i have no idea what anything you said meant. thank you for trying though

Answer 8

All right. How do you pick up this info? Are in a real classroom, or are you taking an online course, or what?

Answer 9

Have you seen the "vertex form of the equation of a parabola" before?

Answer 10

im taking an online course and the videos that are suppose to teach us suck at explaining things

Answer 11

Have you no reference book or anything like that? Nothing but videos?

Answer 12

only videos.

Answer 13

what a shame. I couldn't imagine learning material like this from only videos.

In this problem you are told that the vertex of the graph of the given quadratic function is at (-5,-27). Would you be able to sketch a rough graph of the function (which is a parabola), based upon that information?

Answer 14

By asking this question, I'm trying to assess what you know about this topic. You don't actually have to sketch the graph for me; rather, I just want to know whether your could nor not, based upon what you know.

Answer 15

Sorry to learn that you're now off-line. I really wanted to help you, but found that you've apparently just disappeared without notice.