Mathematics
10 Online
OpenStudy (anonymous):
Find the difference.
2x / 4xy - 6 / 2x
a. x - 3 / y
b. x - 6y / 2xy
c. x - 3 / 2xy - x
d. -5 / 2
Help please.
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OpenStudy (anonymous):
@elementwielder
OpenStudy (anonymous):
\[\frac{ 2x }{ 4xy }- \frac{ 6 }{ 2x }\]
OpenStudy (anonymous):
correct?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
simplify the individual terms first.
2x/(4xy) = 2/4 * x/x * 1/y
= ?
6/(2x) = 6/2 * 1/x
= ?
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OpenStudy (anonymous):
It is B correct?
OpenStudy (anonymous):
simplify the equation so it is this\[\frac{ 1 }{ 2y }-\frac{ 3 }{ x }\]
OpenStudy (anonymous):
B is not correct because where would you have drawn the extra "y" from?
OpenStudy (anonymous):
so we automatically rule that out
OpenStudy (anonymous):
B is right.
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OpenStudy (anonymous):
how so?
OpenStudy (anonymous):
(9/3x) - (4/2x^2) =
(3/x) - (2/x^2) =
3x/x^2 - 2/x^2 =
(3x - 2)/x^2
OpenStudy (anonymous):
wrong one xD
OpenStudy (anonymous):
what lol? which one is wrong?
OpenStudy (anonymous):
x/4xy - 6/2x
= x/2xy - (6/2x)(y/y)
= x/2xy - 6y/2xy
= (x-6y)/2xy
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OpenStudy (anonymous):
its B
OpenStudy (anonymous):
im wondering why in your second step you multiplied y/y to 6/2x
hartnn (hartnn):
to make the denominator common as xy
and yes, its B
hartnn (hartnn):
as 2xy
OpenStudy (anonymous):
oh true... i was thinking they were equal not as on one side of the equation
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OpenStudy (anonymous):
my bad