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Given sin u = .315 and cos v = .759 and u and v are first quadrant angles. Find tan u and tan v using basic and pythagorean identities.
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First use this identity to get \(\cos\):\[ 1=\sin^2x+\cos^2x \implies \cos x=\sqrt{1-\sin^2 x} \]Then divide to get \(\tan\):\[ \tan(x) = \frac{\sin x}{\cos x} = \frac{\sin x}{\sqrt{1-\sin^2 x}} \]
why do I try to find cos first?
do I try to find cos and sin?
and to find sin do I input sin v= sqrt 1-cos^2 ?
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