Question

How do you solve -x + 3 > 7 ?

Answer 1

\(\Large\color{blue}{ -x + 3 > 7 }\)

1) subtract 3 from both sides
2) divide/multiply both sides by/times ` - 1 ` .

Answer 2

thank you but do you have a full explanation for it though ?

Answer 3

this is the full explanation, just follow the steps.

Answer 4

\(\Large\color{blue}{ -x + 3 > 7 }\)
\(\Large\color{blue}{ -x + 3 \color{red}{ -3 } > 7 \color{red}{ -3 } }\)

\(\Large\color{blue}{ -x > 4 }\)
\(\Large\color{blue}{ -x\color{red}{ \times~ (-1) } > 4\color{red}{ \times~ (-1) } }\)

when multiplying/dividing by negative, you change the sign... so
\(\Large\color{blue}{ x < -4 }\)

Answer 5

yesss omg thank you so much (:

Answer 6

anytime

Answer 7

notice that when you multiply or divide by a negative you have to switch the > to < and vice versa.

However, it is *always* safe to add or subtract , so when you see
-x > 4
you could add +x to both sides
-x + x > 4 + x
0 > 4 + x
then add -4 to both sides. You get
-4 > x

or
x < -4 (means the same thing)