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Which factor do you cancel from the numerator and denominator to simplify x^2 + 3x -4 / x^2 -16?
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\(\Large\color{red}{ x^2 + 3x -4 =(x-1)(x+4) }\) \(\Large\color{blue}{ x^2 -16 =(x-4)(x+4) }\)
x - 3
That's what I guess. x + 3 and x - 3 cancel out, so it makes sense
x+3 and x-3 don't cancel..
(x-3)? o.o When Solomon factored both the numerator and denominator, he factored each into two binomials. (x+4) is the common factor in both the numerator and denominator. That factor will cancel, and you will be left with (x-1) in the numerator and (x-4) in the denominator.
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Okay x.x Thanks, Bunni ♥
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