You spin the spinner below once. What is the probability that the arrow will land on 3? link to Picture-->http://lv.k12.com/mediaFiles/Ninth_Grade/Math/Unit18066/Lesson69950/VHS_PA_S2_06_L205_L305_LQ_Q1.gif A.1/8 B.1/4 C.3/8 D.8
I think C.3/8
proportion of the area
Probability of landing on 3 = (# of spaces that are labelled '3')/(# of spaces total)
how much of the circle has a 3?
The answer is A, 1/8. Since there are a total of 8 possibilities,and the number 3, being one of the 8 possibilities.
probability(event) = (number of desired outcomes)/(total number of possible outcomes) number of desired outcomes --------> How many spaces have a 3? total number of possible outcomes ---> How many spaces are there? Divide the number of spaces with 3 by the total number of spaces
hmmmm
it is not the number of spaces for a problem like this, it is an area problem
In math problems with figures, we are not allowed to conclude any dimensions from the figures unless we are specifically told to do so. This is simply a common type of spinner with 8 different numbers, and we assume an equal probability of landing on any of them.
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