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Mathematics 20 Online
OpenStudy (anonymous):

x^2+x-6=0

OpenStudy (anonymous):

factor it

OpenStudy (anonymous):

how ?

OpenStudy (anonymous):

guess

OpenStudy (anonymous):

think of two numbers whose product is \(-6\) and that add up to \(1\)

OpenStudy (anonymous):

?

OpenStudy (anonymous):

I mean 2x^2-6=0

OpenStudy (anonymous):

no you have no like terms to combine here

OpenStudy (anonymous):

factor means to write as a product, not to combine like terms

OpenStudy (anonymous):

i.e. write \[x^2+x-6\] as \[(x+a)(a+b)\]for some numbers \(a,b\)

OpenStudy (anonymous):

so 2, -3 is the answer ?

OpenStudy (anonymous):

i don't know did you factor it?

OpenStudy (anonymous):

hold on I'll show my work

OpenStudy (anonymous):

you have to do it step by step, not jump to the answer

OpenStudy (anonymous):

x = (-1 +/- sqrt(1^2 - 4(1)(-6))) / (2*1) x = (-1 +/- sqrt(1 + 24)) / 2 x = (-1 +/- sqrt(25)) / 2 x = (-1 +/- 5) / 2 x = (4 or -6) / 2 x = 2 or -3

OpenStudy (anonymous):

you lost me \[x^2+x-6=0\\ (x+3)(x-2)=0\] therefore \[x+3=0\iff x=-3\] or \[x-2=0\iff x=2\]

OpenStudy (anonymous):

oh I forgot to split up the 6 like that ! I haven't done this kind of problem in the longest

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