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OpenStudy (anonymous):
x^2+x-6=0
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OpenStudy (anonymous):
factor it
OpenStudy (anonymous):
how ?
OpenStudy (anonymous):
guess
OpenStudy (anonymous):
think of two numbers whose product is \(-6\) and that add up to \(1\)
OpenStudy (anonymous):
?
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OpenStudy (anonymous):
I mean 2x^2-6=0
OpenStudy (anonymous):
no you have no like terms to combine here
OpenStudy (anonymous):
factor means to write as a product, not to combine like terms
OpenStudy (anonymous):
i.e. write
\[x^2+x-6\] as
\[(x+a)(a+b)\]for some numbers \(a,b\)
OpenStudy (anonymous):
so 2, -3 is the answer ?
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OpenStudy (anonymous):
i don't know
did you factor it?
OpenStudy (anonymous):
hold on I'll show my work
OpenStudy (anonymous):
you have to do it step by step, not jump to the answer
OpenStudy (anonymous):
x = (-1 +/- sqrt(1^2 - 4(1)(-6))) / (2*1)
x = (-1 +/- sqrt(1 + 24)) / 2
x = (-1 +/- sqrt(25)) / 2
x = (-1 +/- 5) / 2
x = (4 or -6) / 2
x = 2 or -3
OpenStudy (anonymous):
you lost me
\[x^2+x-6=0\\
(x+3)(x-2)=0\] therefore
\[x+3=0\iff x=-3\] or
\[x-2=0\iff x=2\]
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OpenStudy (anonymous):
oh I forgot to split up the 6 like that ! I haven't done this kind of problem in the longest
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