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English 26 Online
OpenStudy (anonymous):

Which calculation set-up would be correct to determine the volume of concentrated hydrochloric acid (12.0 M HCl) that is required to make 500.0 milliliters of a 6.0 M HCl? 12.0 M * 0.500 l = 6.0 M * V2 12.0 M * 6.0 M = 0.500 l * V2 12.0 M * V1 = 6.0 M * 0.500 l 6.0 M * V1 = 12.0 M * 0.500 l (12.0 M + 6.0 M) = 0.500 l * V2

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