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Chemistry 16 Online
OpenStudy (anonymous):

Question. Help appreciated.

OpenStudy (anonymous):

OpenStudy (anonymous):

@trueseminole

OpenStudy (anonymous):

ok so ill do this

OpenStudy (anonymous):

let's start with option 1

OpenStudy (anonymous):

M1V1 = M2V2 right?

OpenStudy (anonymous):

Yup.

OpenStudy (anonymous):

nah let's just do C beuase thats the answer ill just show you how i got it

OpenStudy (anonymous):

The method will be enough. Or else I'll be tempted to copy it. My jammed brain would remain forever jammed.

OpenStudy (anonymous):

closed the tap by accident

OpenStudy (anonymous):

okay so i kinda lost my way here

OpenStudy (anonymous):

im sorry this is difficult to solve

OpenStudy (anonymous):

@wio

OpenStudy (anonymous):

@iambatman

OpenStudy (anonymous):

Yes, \[M2 = \frac{ (M1~ \times~ V1) }{ V2 }\]

OpenStudy (anonymous):

I'm assuming you know what everything means in this formula?

OpenStudy (anonymous):

The M2 obtained in the first case will be M1 in the next case ? And we are supposed to continue in this manner ?

OpenStudy (anonymous):

You'll have to convert to litres as well.

OpenStudy (anonymous):

\[M2= \frac{ 5.6~ \times ~ 0.046}{ 0.116 } = 2.22 \] \[M2 = \frac{ (2.22~\times~0.058) }{ 0.248 } = ...\] Etc, I left the units out but it's pretty obvious what they are, and yes.

OpenStudy (anonymous):

I'm getting the final answer as 0.157 M. Is that right ?

OpenStudy (anonymous):

I don't know, I'm not doing it all.

OpenStudy (anonymous):

But long as you understand what is going on, it should be right.

OpenStudy (anonymous):

Okay. Thank you very much, Batman / Dark Knight (whichever you prefer).

OpenStudy (anonymous):

Lol, np :)

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