Consider the sequence 130, 143, 156, 169, ... Write an explicit formula to represent the arithmetic sequence and use it to find the 13th term. A. A(n) = 130 + 13n; 286 B. A(n) = 130 + (n-1)13; 299 C. A(n) = 130 + 13n; 299 D. A(n) = 130 + (n-1)13; 286
C
sorry D
so vich vone is it
Had you 130, how would you get to 143? Had you 143, how would you get to 156? What kind of sequence is this?
Formula: \[a_{n}=a _{1}+d(n-1)\] a1 is the first term, or 130. d is the common difference-13 n is the number in the sequence. When solving for the 13th term, it will be n=13 Your formula is: \[a_{n}=130+13(13-1)\] just solve.
@trexnapora: OpenStudy's purpose is to help you learn your subject material; it is NOT a source of free answers that yuo obtain with no effort on your part. I notice you've not answered the questions I asked you, which were meant to help you determine how we get from one term to the next in yur sequence. Contribute something to this problem solving, please. You might want to read @AnonymousBeast 's contribution and follow his/her advice.
im sorry but if you are here to help then you might as well help yourself to spell correctly
keep typing @mathmale
Fortunately (!) I'm not certain to whom you were directing that inappropriate comment. Instead, I'm letting it slide and asking whether you, $trexnapora, are going to try to finish this problem that you posted.
yes i just need the equation
Four equations are given as possible answers. AnonymousBeast has all but given you the answer. I gave you hints by asking you questions. What more do you need or want along the way to choosing the correct answer yourself?
@mathmale is just here to help, @trexnapora
so you don't need to be rude
k i got the answer tnx for b ing patient
@trexnapora, he wasn't trying to be impatient. OpenStudy has received a lot of hate for being known as a website for free answers. @mathmale is simply trying to rid the site of that name.
cool
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