Using the graph of f(x) = log10x below, approximate the value of y in the equation 10y = 3.
y ≈ 0.01 y ≈ 1.48 y ≈ −2.01 y ≈ 0.78
@Hero @jim_thompson5910
The function is \[\Large f(x) = \log_{10}(x)\] right?
Yep
Replace f(x) with y. Then convert to exponential form. \[\Large f(x) = \log_{10}(x)\] \[\Large y = \log_{10}(x)\] \[\Large 10^{y} = x\]
Then on the right side, replace x with 3 to get \[\Large 10^{y} = 3\]
After all that, convert back to logarithmic form \[\Large 10^{y} = 3\] \[\Large y = \log_{10}(3)\]
So what you need to do is use the graph to find the y coordinate of the point on the curve when x = 3
Ok
what is that y value?
0.48?
That's not a choice though.
Alternatively, another approach is to realize that \(10^0 = 1\) \(10^1 = 10\) So that means the value of y must be \(0 < y < 1\)
From this information you can easily eliminate the middle two options.
Actually, option 2 might be a typo
Ok, what I was doing earlier was plugging the choices into log(10)y. The closest I got was 0.01 = y and that disproved 10^y=3.
Option 2? What do you think is the alternative?
\(y \approx 0.48\)
Or the typo could be in option 4
I don't know which one, but if I had to pick, I'd choose option 2
Talk to your teacher about it.
That would make a lot of sense. I copied the answers over here correctly, but perhaps my source/test has an error.
Your test?
Assignment. Any way, she is unreachable today, so I'll just wing it. Thank you for your help.
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