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OpenStudy (anonymous):
Given that P = (-9, 2) and Q = (-10, 9), find the component form and magnitude of 2vector PQ.
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jimthompson5910 (jim_thompson5910):
What's the component form of vector PQ ?
OpenStudy (anonymous):
I'm not sure
OpenStudy (anonymous):
Is it like p - q or something
jimthompson5910 (jim_thompson5910):
subtract the corresponding coordinates (tail - head)
jimthompson5910 (jim_thompson5910):
Q is the tail, so Q - P
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OpenStudy (anonymous):
so -10--9 & 9-2
jimthompson5910 (jim_thompson5910):
-10 - (-9) = -10 + 9 = -1
9 - 2 = 7
jimthompson5910 (jim_thompson5910):
so PQ is the vector < -1, 7 >
jimthompson5910 (jim_thompson5910):
then you double every coordinate to get 2*PQ
OpenStudy (anonymous):
so I get 12
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jimthompson5910 (jim_thompson5910):
double each coordinate:
-1*2 = -2
7*2 = 14
So the vector 2*PQ is < -2, 14 >
OpenStudy (anonymous):
with sort of 200 right
jimthompson5910 (jim_thompson5910):
200?
OpenStudy (anonymous):
sqrt*
jimthompson5910 (jim_thompson5910):
where are you getting that?
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jimthompson5910 (jim_thompson5910):
oh the magnitude of 2*PQ
OpenStudy (anonymous):
Yeah lol
jimthompson5910 (jim_thompson5910):
yeah the magnitude of 2*PQ is \(\Large \sqrt{200}\)
you can simplify that though
OpenStudy (anonymous):
Thank you (:
jimthompson5910 (jim_thompson5910):
\[\Large \sqrt{200} = \sqrt{100*2}\]
\[\Large \sqrt{200} = \sqrt{100}*\sqrt{2}\]
\[\Large \sqrt{200} = 10*\sqrt{2}\]
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