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Chemistry 9 Online
OpenStudy (anonymous):

Can someone help me on figuring out the pK for ionization constants: K=1.8x10^-5. We haven't learned this in class yet.

OpenStudy (anonymous):

"p" stands for "-log" so pK is the same as -logK. More specifically in this case, pK = -log(1.8E-5) which is 4.745

OpenStudy (anonymous):

Ohh! Ok. Thank you so much!! So that's why pH is -log[H+] too, right?

OpenStudy (anonymous):

Yes

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