Question

http://prntscr.com/3y6o7z

Answer 1

@zepdrix

Answer 2

\[Sin x (2Sinx - 1) = 0\] is what I got after some work and I can't figure out how to get any further

Answer 3

yes your work is right
then either sinx = 0 => x = 0 , pi
or sinx = 1/2 => x = pi/3

Answer 4

Can you re-write that in the equation editor? I'm all over the place right now

Answer 5

\[sinx = 0 \rightarrow x = { 0 , \frac{ \pi }{ 2 } }\]
\[2sinx -1 = 0 \rightarrow sinx = \frac{ 1 }{ 2 } \rightarrow x = \frac{ \pi }{ 6 }\]

Answer 6

Why is Trig so confusing???

Answer 7

Woops lemme fix a small mistake he made,
\[\Large\rm \sin x=0,\qquad\to\qquad x=0,~ \pi\]\[\Large\rm \sin x=\frac{1}{2},\qquad\to\qquad x=\frac{\pi}{6},~\frac{5\pi}{6}\]

Answer 8

So what is that? The answer?

Answer 9

Yes.
Do you have trouble remembering your special angles? :o

Answer 10

Trig is so awesome +_+
Gotta really get an understanding of that unit circle though.

Answer 11

I don't even have the trig identities memorized

Answer 12

I have a sheet taped to the wall in front of my Monitor with all the Trig identities on it

Answer 13

Trig sounds fun. But it seems very hard at first. I was the best in my class with math. Now that trig comes along, it's starting to piss me off

Answer 14

Lol poor guy :3

Answer 15

What are the special angles anyways?

Answer 16

These are the special angles in the first quadrant.

Answer 17

Cosine of an angle corresponds to the x component while the Sine corresponds to the y or vertical component.