Question

Need help finding the parallel lines to
y=-3x-6;(-1,5)

Answer 1

now u just rearrange that in y=mx+b form to make it look nice

Answer 2

sorry a mistake that shud be

Answer 3

you see -3 must be a slope so it is parallel and you can write a line in this form so it goes through this point given like so
y-5=-3(x-(-1))

y-5=-3(x+1)
y-5=-3x-3
y=-3x+2

Answer 4

to make it more clear the general form is

Answer 5

if it goes through the time (a,b) and has to be parallel to line with slope m, then
y-b=m(x-a)

Answer 6

ok thanks

Answer 7

there are other ways to do it too

Answer 8

like say know the line intetrcept form
y=mx+b

Answer 9

u know it has slope -3 so
y=-3x+b
now sub in that point we are given to find what b must be
5=-3(-1)+b
b=5-3=2
so
y=-3x+2

Answer 10

this is called the slope intercept form. m= slope and b= y-intercept

Answer 11

ok not I have to find the perpendicular lines to y=1/3x+1;(4,2)

Answer 12

for a perpendicular line, you have to take the negative reciprocal of the slope

Answer 13

and repeat the same steps to find the b, for that given point