Find dy/dx given that y² =x(3-x)². State the values of x for which dy/dx is: (a) zero (b) infinite. answer to (a) ± (3/2√x-(3/2)√x) answer to (b) is 1 HI CAN YOU SHOW ME STEP BY STEP HOW TO GET X=± (3/2√x-(3/2)√x). AS AM GETTING A DIFFERENT ANSWER (x^2=9/12x) PS and part b how do i get the 1 thanks
and so on
thanks just one question what i have done is this
(3x^2-12x+9)/2(x(3-x))^1/2
and then we simplify rational functions, am i on the right track?
hold on ! let me see
why are you doing this step?
i have differentiated the function y² =x(3-x)² using implicit differentiation to get
oh~ i see
2ydy/dx=(3x^2-12x+9)
we then equate dy/dx=0 and solve for x
remembering to put the 2 in the denominator
(3x^2-12x+9)/2(x(3-x))^1/2
also remember that y² =x(3-x)² square root to find y
correct me if am wrong thanks
let me think for a while....
i have made a mistake the denominator should be
(3x^2-12x+9)/2(x^1/2(3-x)) the square root of x not (3-x)
implicit way
i think i have got it :-)
I think this question is not good to use implicit way. so ,you can see the file(1).
check if this is correct we will have (-3/2√x)(x-1)
then when you simplify you get the answer
sorry,my file(10.1) is wrong ,but the file(1) is correct.....so,now, i will rewrite implicit way.....
here is the file (10.1)fixed
sorry i don't get how you got the denominator
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