In the reaction of H2 + O2 ---> 2H2O, if 7.28 moles of O2 is used, how many moles of H2O will be generated?
Hello @Mateaus !
Hello
I don't remember how to start off this problem.
According to the given reaction one mole of O\(_2\) will react with one mole of H\(_2\) to form 2 moles of H\(_2\)O.
Now 7.28 moles of O\(_2\) will form 7.28*2=14.56 moles of H\(_2\)O
Getting my points ?
In the reaction of 2H2 + O2 ---> 2H2O, if 7.28 moles of O2 is used, how many moles of H2O will be generated? I forgot to add a 2 in front of H2
Would it still work the same way?
yes, but it will change if hydrogen is given and H2O is to be determined.
getting ?
How come the hydrogen doesn't affect with the 7.28moles of the oxygen?
Because we are assuming that the hydrogen is already present in the required amount
Even though there is 2 moles of hydrogen?
We r just calculating the oxygen's part !
yes, in the new equation u gave 2 moles of hydrogen is reacting with one mole of oxygen to produce 2 moles of water
so if i ask, how much water will be produced if one mole of oxygen is used. Then u'll say 2 moles. If i ask how many moles of water will be produced if i use one mole of hydrogen, then u'll say one mole.
getting it ?
I am still thinking on the second one
guys.....again it was supposed to be an easy question,...
For 2H2 + O2 ---> 2H2O 2H2 ------> 2H2O 1O2------> 2H20
Yes, but if I have just 1 mole of hydrogen, then on the product side oxygen wouldn't be balanced
yes, but the question has given no info about hydrogen.
so we will consider that hydrogen is present in sufficient amount
I mean hydrogen will be balanced if they both are 1 mole but wouldn't that affect the oxygen since on the reactan side there is 2 of oxygen while on the product side they will be just 1
or I simply ignore that and look to both hydrogens?
in the product side one mole of water is produced...it contains two moles of hydrogen
so reactant and product side gets balanced this way
H2 + O2 ---> 2H2O ratio between O2 and H2 is 1:1 that is why mole of O2 = mole of H2 now we see the ratio between O2 and H2O or H2 and H2O (doesn't matter since mole is same for both H2 and O2) so ratio is 1:2 means ratio 1 is ---7.28 (because O2 is 1 and H2O is 2) ratio 2 is ---- X X= 2* 7.28 /1 = 14.56 moles of H2O
i just noticed @Mateaus the reaction is not balanced!!!
It will be 2H2 + O2----> 2H2O
balance it and do the rest in the same way basically
is it clear @Mateaus ?
"If i ask how many moles of water will be produced if I use one mole of hydrogen, then u'll say one mole." I am trying to understand this one yet.
if I balanced it then it will go back to 2H2 + O2 --> 2H2O though
btw lol the answer will still be same
@Mateaus what is the answer that u have?
14.56 but I am trying to understand this part lol
because 2 moles of hydrogen produce two moles of water, so one mole of hydrogen will react with half mole of oxygen to form one mole of water.
alright did u understand what i did? do u know how to work with ratio?
if I have 1H +O2 --> 1H2O then O in the produc side won't be balanced.
1H + 1/2 O2----> 1H2O
@Abhisar its H2 + 1/2 O2----> 1H2O
\(\color{blue}{\text{Originally Posted by}}\) @Abhisar 1H2 + 1/2 O2----> 1H2O \(\color{blue}{\text{End of Quote}}\)
we are talking in moles...are u getting it now ?
oh I remember balancing it by diving both sides by 2 in order to make them balanced.
yes...
ah ok all is clear now haha. Thanks you two :D
for questions like these u just need to find out that how much of the interested reactant produces how much product. Then u can calculate the answer using unitary method. like in this 2 mole of hydrogen produces 2 mole of water, so 1 mole of hydrogen will produce 1 mole of water and so on.
so if I had 2O2(just as example) and the question says if 7.28moles of O2 is used. I would first multiply the 7.28moles to the 2 of the O2 and then the result of that multiply by the moles of water in the product side to obtain the moles of H2O generated.
2 is coefficient.... its not mole @Mateaus
is not the number of coefficient, the number of moles of something?
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