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Chemistry 19 Online
OpenStudy (anonymous):

In the reaction of H2 + O2 ---> 2H2O, if 7.28 moles of O2 is used, how many moles of H2O will be generated?

OpenStudy (abhisar):

Hello @Mateaus !

OpenStudy (anonymous):

Hello

OpenStudy (anonymous):

I don't remember how to start off this problem.

OpenStudy (abhisar):

According to the given reaction one mole of O\(_2\) will react with one mole of H\(_2\) to form 2 moles of H\(_2\)O.

OpenStudy (abhisar):

Now 7.28 moles of O\(_2\) will form 7.28*2=14.56 moles of H\(_2\)O

OpenStudy (abhisar):

Getting my points ?

OpenStudy (anonymous):

In the reaction of 2H2 + O2 ---> 2H2O, if 7.28 moles of O2 is used, how many moles of H2O will be generated? I forgot to add a 2 in front of H2

OpenStudy (anonymous):

Would it still work the same way?

OpenStudy (abhisar):

yes, but it will change if hydrogen is given and H2O is to be determined.

OpenStudy (abhisar):

getting ?

OpenStudy (anonymous):

How come the hydrogen doesn't affect with the 7.28moles of the oxygen?

OpenStudy (abhisar):

Because we are assuming that the hydrogen is already present in the required amount

OpenStudy (anonymous):

Even though there is 2 moles of hydrogen?

OpenStudy (abhisar):

We r just calculating the oxygen's part !

OpenStudy (abhisar):

yes, in the new equation u gave 2 moles of hydrogen is reacting with one mole of oxygen to produce 2 moles of water

OpenStudy (abhisar):

so if i ask, how much water will be produced if one mole of oxygen is used. Then u'll say 2 moles. If i ask how many moles of water will be produced if i use one mole of hydrogen, then u'll say one mole.

OpenStudy (abhisar):

getting it ?

OpenStudy (anonymous):

I am still thinking on the second one

OpenStudy (somy):

guys.....again it was supposed to be an easy question,...

OpenStudy (abhisar):

For 2H2 + O2 ---> 2H2O 2H2 ------> 2H2O 1O2------> 2H20

OpenStudy (anonymous):

Yes, but if I have just 1 mole of hydrogen, then on the product side oxygen wouldn't be balanced

OpenStudy (abhisar):

yes, but the question has given no info about hydrogen.

OpenStudy (abhisar):

so we will consider that hydrogen is present in sufficient amount

OpenStudy (anonymous):

I mean hydrogen will be balanced if they both are 1 mole but wouldn't that affect the oxygen since on the reactan side there is 2 of oxygen while on the product side they will be just 1

OpenStudy (anonymous):

or I simply ignore that and look to both hydrogens?

OpenStudy (abhisar):

in the product side one mole of water is produced...it contains two moles of hydrogen

OpenStudy (abhisar):

so reactant and product side gets balanced this way

OpenStudy (somy):

H2 + O2 ---> 2H2O ratio between O2 and H2 is 1:1 that is why mole of O2 = mole of H2 now we see the ratio between O2 and H2O or H2 and H2O (doesn't matter since mole is same for both H2 and O2) so ratio is 1:2 means ratio 1 is ---7.28 (because O2 is 1 and H2O is 2) ratio 2 is ---- X X= 2* 7.28 /1 = 14.56 moles of H2O

OpenStudy (somy):

i just noticed @Mateaus the reaction is not balanced!!!

OpenStudy (abhisar):

It will be 2H2 + O2----> 2H2O

OpenStudy (somy):

balance it and do the rest in the same way basically

OpenStudy (abhisar):

is it clear @Mateaus ?

OpenStudy (anonymous):

"If i ask how many moles of water will be produced if I use one mole of hydrogen, then u'll say one mole." I am trying to understand this one yet.

OpenStudy (anonymous):

if I balanced it then it will go back to 2H2 + O2 --> 2H2O though

OpenStudy (somy):

btw lol the answer will still be same

OpenStudy (somy):

@Mateaus what is the answer that u have?

OpenStudy (anonymous):

14.56 but I am trying to understand this part lol

OpenStudy (abhisar):

because 2 moles of hydrogen produce two moles of water, so one mole of hydrogen will react with half mole of oxygen to form one mole of water.

OpenStudy (somy):

alright did u understand what i did? do u know how to work with ratio?

OpenStudy (anonymous):

if I have 1H +O2 --> 1H2O then O in the produc side won't be balanced.

OpenStudy (abhisar):

1H + 1/2 O2----> 1H2O

OpenStudy (somy):

@Abhisar its H2 + 1/2 O2----> 1H2O

OpenStudy (abhisar):

\(\color{blue}{\text{Originally Posted by}}\) @Abhisar 1H2 + 1/2 O2----> 1H2O \(\color{blue}{\text{End of Quote}}\)

OpenStudy (abhisar):

we are talking in moles...are u getting it now ?

OpenStudy (anonymous):

oh I remember balancing it by diving both sides by 2 in order to make them balanced.

OpenStudy (abhisar):

yes...

OpenStudy (anonymous):

ah ok all is clear now haha. Thanks you two :D

OpenStudy (abhisar):

for questions like these u just need to find out that how much of the interested reactant produces how much product. Then u can calculate the answer using unitary method. like in this 2 mole of hydrogen produces 2 mole of water, so 1 mole of hydrogen will produce 1 mole of water and so on.

OpenStudy (anonymous):

so if I had 2O2(just as example) and the question says if 7.28moles of O2 is used. I would first multiply the 7.28moles to the 2 of the O2 and then the result of that multiply by the moles of water in the product side to obtain the moles of H2O generated.

OpenStudy (somy):

2 is coefficient.... its not mole @Mateaus

OpenStudy (anonymous):

is not the number of coefficient, the number of moles of something?

OpenStudy (abhisar):

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