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Algebra 21 Online
OpenStudy (anonymous):

MEDAL AWARDED ON SPOT

OpenStudy (anonymous):

What do you need hun? (:

OpenStudy (anonymous):

OpenStudy (anonymous):

Okay. Just give me a second to work it out!

OpenStudy (anonymous):

Okay, so I am going to explain it okay? Here it is:

OpenStudy (anonymous):

Okay, so we are trying to simplify 2√20 + 8√45 + √80 First, we simplify 2√0. If you use a guess and check method, you see that -12 = 1 and 12 = 1. Since 1 < 0 < 1 the next logical step would be checking 02. 02 = 0 x 0 02 = 0 <--- We match our original number!!! :D Multiplying by our outside constant, we get 2 x 0 = 0 Therefore, 2√0 = ±0 Now we simplify 8√0. If you use a guess and check method, you see that -12 = 1 and 12 = 1. Since 1 < 0 < 1 the next step would be checking 02. 02 = 0 x 0 02 = 0 <--- We match our original number (AGAIN!)!!! Multiplying by our outside constant, we get 8 x 0 = 0 Therefore, 8√0 = ±0 the next step is to simplify √80. Checking square roots, we see that 82 = 64 and 92 = 81. Since our answer is not an integer, we will try simplify it into the product of an integer and a radical. We do this by listing each product combo of 80 checking for integer square root values below: √80 = √1√80 √80 = √2√40 √80 = √4√20 √80 = √5√16 √80 = √8√10 Like that^^^^^ From that list, the highest factor that has an integer square root is 16. Therefore, we use the product combo √80 = √16√5 Evaluating square roots, we see that √16 = 4 Simplifying our product of radicals, we get our answer: √80 = 4√5 Simplifying the original expression, we get: Group Constants → 0 Group √5 terms → 4√5 = 4√5 Build our final simplified answer: 0 + 4√5 Understand?

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