Question

Baking soda (NaHCO3) is an active ingredient in some antacids. Determine the percent composition of oxygen in baking soda.

19%
21%
42%
57%

Answer 1

@Abhisar

Answer 2

@DW101796

Answer 3

@Hero

Answer 4

@sammixboo @Abhisar @dan815 @deshawn1 @dcknox123 @Caitlyn_Morgan @Luigi0210 @livelovechloeee @luiss_69

Answer 5

42%

Answer 6

Have u tried it ur self ?

Answer 7

no i have no clue how to do it

Answer 8

First calculate the molecular mass of NaHCO\(_3\).

Answer 9

Na is 22.99
H is 1.01
C is 12.01
O is 16.00

Answer 10

so molecular mass will be ?

Answer 11

wait so am I to add all of these
Na is 22.99
H is 1.01
C is 12.01
O is 16.00

Answer 12

yes. Don't forget to add O three times. Because its O\(_3\)

Answer 13

52.01 what difference would it make to add 0 three times

Answer 14

not 0, I said O (oxygen)

Answer 15

Molecular mass will be 23+1+12+(16*3)=84

Answer 16

got it ?

Answer 17

I have rounded off the figures

Answer 18

yep. how do you know what the total mass of the element is

Answer 19

Now, % composition = \(\huge\frac{Total~mass~of~element}{Molecular~mass~of~Compound}\) * 100

Answer 20

=\(\huge\frac{16*3}{84}\) *100 = \(\huge\frac{48}{84}\) *100= 57%

Answer 21

I see but where is 48 coming from?

Answer 22

Mass of one oxygen atom is 16 and there are 3 oxygen atoms in the compound. So total mass of oxygen element = 16*3=48

Answer 23

AHH I See Thanks for teaching mE!

Answer 24

\(\color{red}{\huge\bigstar}\huge\text{You're Most Welcome! }\color{red}\bigstar\)
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Answer 25

@dcknox123 Seeking/Giving direct/Just answers is against the \(\large\sf\color{red}{\underline{\href{ /code-of-conduct}{code~of~conduct}}}\) of openstudy.