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Mathematics 17 Online
OpenStudy (anonymous):

help

OpenStudy (anonymous):

Find the point C such that AC and BC form a 2:3 ratio. (−1, 1.2) (−0.6, 3) (0, 2.4) (0.5, 2)

OpenStudy (anonymous):

I don't know

OpenStudy (anonymous):

@ShailKumar

OpenStudy (anonymous):

Tell me the coordinates of A and B

OpenStudy (anonymous):

A (-3, 5) B (3, 0)

OpenStudy (anonymous):

Good! Now, see the situation in the figure |dw:1404239855683:dw|

OpenStudy (anonymous):

we have to use the slope formula?

OpenStudy (anonymous):

We want to find the coordinates of the point which divides AB in a ratio of m1:m2.

OpenStudy (anonymous):

i don't understand

OpenStudy (anonymous):

If the coordinates of this point be (x,y) then \[x = \frac{ m _{1}x _{2} + m _{2} x _{1} }{ m _{1}+m _{2}}\]

OpenStudy (anonymous):

And y = \[y = \frac{ m _{1}y _{2} + m _{2} y _{1} }{ m _{1}+m _{2}}\]

OpenStudy (anonymous):

Now A (-3, 5) gives you x1 = -3 and y1 = 5; B (3, 0) gives you x2 = 3 and y2 = 0 And m1:m2 is 2:3, so m1 = 2 and m2 = 3

OpenStudy (anonymous):

Put these values in the formula and get the values of x and y.

OpenStudy (anonymous):

@shinebrightlikeadimon Could you find x and y ?

OpenStudy (anonymous):

let me see

OpenStudy (anonymous):

y = 15 / 5?

OpenStudy (anonymous):

Yes, y = 3

OpenStudy (anonymous):

x = -0.6

OpenStudy (anonymous):

is that correct?

OpenStudy (anonymous):

Great! So the point C is (-0.6,3).

OpenStudy (anonymous):

THANK YOU!

OpenStudy (anonymous):

You are welcome :)

OpenStudy (anonymous):

A quadrilateral PQRS is inscribed in a circle, as shown below: What is the measure of arc PQR? 210° <--- my answer 255° 105° 75°

OpenStudy (anonymous):

@ShailKumar

OpenStudy (anonymous):

Correct!

OpenStudy (anonymous):

thanks

OpenStudy (anonymous):

Box A has a volume of 24 cubic meters. Box B is similar to Box A. To create Box B, Box A's dimensions were multiplied by four. What is the volume of Box B? 6 m3 1,536 m3 384 m3 <--- my answer 96 m3

OpenStudy (anonymous):

No. This time you are wrong. :(

OpenStudy (anonymous):

If the side of the cube A is s then its volume is s^3. Right ?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

i think

OpenStudy (anonymous):

The side of the cube B is 4s, So it's volume should be (4s)^3 i.e 64 s^3. Right ?

OpenStudy (anonymous):

whats i.e?

OpenStudy (anonymous):

We are assuming that boxes are cubical. i.e stands for "that is"

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

now what?

OpenStudy (anonymous):

But s^3 is 24 cubic meters

OpenStudy (anonymous):

So volume of B should be 64*s^3 = ??

OpenStudy (anonymous):

so 64 x 24?

OpenStudy (anonymous):

1536

OpenStudy (anonymous):

Find the diameter of a cone that has a volume of 29.31 cubic inches and a height of 7 inches. Use 3.14 for pi. 4 inches <---- my answer 2 inches 8 inches 6 inches

OpenStudy (anonymous):

How did you get that ?

OpenStudy (anonymous):

how did i get 4 ?

OpenStudy (anonymous):

Yes

OpenStudy (anonymous):

V =1/3* pi * r^2 * h

OpenStudy (anonymous):

Ok, I got it. Your answer is correct :)

OpenStudy (anonymous):

29.31 = 1/3 * 3.14 * r^2 * 7 so 29.31 = 7.326 x r^2 29.32/7.326 = r^2 4 = r^2

OpenStudy (anonymous):

and r = 2 but r is half the diameter so its 4

OpenStudy (anonymous):

am i correct

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