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Mathematics 20 Online
OpenStudy (anonymous):

Use the given conditions to write an equation for the line in point-slope form. Passing through (-5, -7) and (-8, -6) I tried to graph this and even find a slope and nothing's coming together >.< Please show me how to solve this properly? http://awesomescreenshot.com/08432s234c

OpenStudy (yanasidlinskiy):

Have you used the formula, y2-y1/x2-x1?

OpenStudy (anonymous):

Yes

OpenStudy (anonymous):

I think I got\[\frac{ 1 }{ -3 }\]

OpenStudy (anonymous):

Ok so we need to write a equation for the line in point slope form. Which means we want it in the form y = mx+b form. First thing you want to do is find the slope using this formula: \[ m = \frac{ y_{2}-y _{1} }{ x _{2}-x _{1} }\] (-5, -7) = (x1, y1) The (1s, and 2s are subscripts here lol) (-8, -6) = (x2, y2) So yes, the slope is -1/3. Now use the point - slope formula \[y-y _{1}=m(x-x _{1})\] and transform it into y =mx+b form.

OpenStudy (anonymous):

Try this now :)

OpenStudy (anonymous):

Or I guess they just want it in point - slope form. So yeah just use the formula I showed ya.

OpenStudy (anonymous):

\[y−y1=m(x−x1) --->y +7= -\frac{ 1 }{ 3 }(x+5)\] is that right so far? and idk what to plug into the x and the y

OpenStudy (anonymous):

Yes!

OpenStudy (anonymous):

Now do the same with x2 and y2, that's what they want I guess.

OpenStudy (anonymous):

\[-6+7=-\frac{ 1 }{ 3 }(-8+5)\] ? o.o

OpenStudy (anonymous):

No, look at your options, you already did the first part, now do the same thing y - y2=m(x-x2) you'll have to equations.

OpenStudy (anonymous):

soooo \[y+7=-\frac{ 1 }{ 3 }(x+5) <---...and...--->y+6=-\frac{ 1 }{ 3 }(x+8)\]

OpenStudy (anonymous):

Yes :)

OpenStudy (anonymous):

yay lol but o.o what do I do with it

OpenStudy (anonymous):

oh wait nvm lol thank you very much ♥

OpenStudy (anonymous):

lol np

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